10010311130231 has 2 divisors, whose sum is σ = 10010311130232. Its totient is φ = 10010311130230.

The previous prime is 10010311130207. The next prime is 10010311130233. The reversal of 10010311130231 is 13203111301001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10010311130231 - 2¹⁰ = 10010311129207 is a prime.

It is a super-2 number, since 2×10010311130231² (a number of 27 digits) contains 22 as substring.

Together with 10010311130233, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10010311130233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005155565115 + 5005155565116.

It is an arithmetic number, because the mean of its divisors is an integer number (5005155565116).

Almost surely, 2^{10010311130231} is an apocalyptic number.

10010311130231 is a deficient number, since it is larger than the sum of its proper divisors (1).

10010311130231 is an equidigital number, since it uses as much as digits as its factorization.

10010311130231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 10010311130231 its reverse (13203111301001), we get a palindrome (23213422431232).

The spelling of 10010311130231 in words is "ten trillion, ten billion, three hundred eleven million, one hundred thirty thousand, two hundred thirty-one".