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100105500503453 is a prime number
BaseRepresentation
bin10110110000101110100000…
…110011000010110110011101
3111010102222210110010101202112
4112300232200303002312131
5101110112031112102303
6552523455420403405
730041245423500044
oct2660564063026635
9433388713111675
10100105500503453
112999556031a9a5
12b2891496a6565
1343b1ba63b4553
141aa11bc5bb55b
15b88e918780d8
hex5b0ba0cc2d9d

100105500503453 has 2 divisors, whose sum is σ = 100105500503454. Its totient is φ = 100105500503452.

The previous prime is 100105500503423. The next prime is 100105500503507. The reversal of 100105500503453 is 354305005501001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 90982944096004 + 9122556407449 = 9538498^2 + 3020357^2 .

It is a cyclic number.

It is not a de Polignac number, because 100105500503453 - 26 = 100105500503389 is a prime.

It is a super-2 number, since 2×1001055005034532 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100105500503423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50052750251726 + 50052750251727.

It is an arithmetic number, because the mean of its divisors is an integer number (50052750251727).

Almost surely, 2100105500503453 is an apocalyptic number.

It is an amenable number.

100105500503453 is a deficient number, since it is larger than the sum of its proper divisors (1).

100105500503453 is an equidigital number, since it uses as much as digits as its factorization.

100105500503453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 22500, while the sum is 32.

The spelling of 100105500503453 in words is "one hundred trillion, one hundred five billion, five hundred million, five hundred three thousand, four hundred fifty-three".