1001100130111 has 2 divisors, whose sum is σ = 1001100130112. Its totient is φ = 1001100130110.

The previous prime is 1001100130097. The next prime is 1001100130139. The reversal of 1001100130111 is 1110310011001.

It is a weak prime.

It is an emirp because it is prime and its reverse (1110310011001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1001100130111 - 2²⁷ = 1000965912383 is a prime.

It is a super-3 number, since 3×1001100130111³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1001100130171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500550065055 + 500550065056.

It is an arithmetic number, because the mean of its divisors is an integer number (500550065056).

Almost surely, 2^{1001100130111} is an apocalyptic number.

1001100130111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001100130111 is an equidigital number, since it uses as much as digits as its factorization.

1001100130111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3, while the sum is 10.

Adding to 1001100130111 its reverse (1110310011001), we get a palindrome (2111410141112).

The spelling of 1001100130111 in words is "one trillion, one billion, one hundred million, one hundred thirty thousand, one hundred eleven".