100110100000033 has 2 divisors, whose sum is σ = 100110100000034. Its totient is φ = 100110100000032.

The previous prime is 100110099999989. The next prime is 100110100000051. The reversal of 100110100000033 is 330000001011001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 54490720259089 + 45619379740944 = 7381783^2 + 6754212^2 .

It is a cyclic number.

It is not a de Polignac number, because 100110100000033 - 2¹³ = 100110099991841 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100110099999965 and 100110100000019.

It is not a weakly prime, because it can be changed into another prime (100110100700033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50055050000016 + 50055050000017.

It is an arithmetic number, because the mean of its divisors is an integer number (50055050000017).

Almost surely, 2^{100110100000033} is an apocalyptic number.

It is an amenable number.

100110100000033 is a deficient number, since it is larger than the sum of its proper divisors (1).

100110100000033 is an equidigital number, since it uses as much as digits as its factorization.

100110100000033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9, while the sum is 10.

Adding to 100110100000033 its reverse (330000001011001), we get a palindrome (430110101011034).

The spelling of 100110100000033 in words is "one hundred trillion, one hundred ten billion, one hundred million, thirty-three", and thus it is an aban number.