100110100000051 has 2 divisors, whose sum is σ = 100110100000052. Its totient is φ = 100110100000050.

The previous prime is 100110100000033. The next prime is 100110100000061. The reversal of 100110100000051 is 150000001011001.

It is an a-pointer prime, because the next prime (100110100000061) can be obtained adding 100110100000051 to its sum of digits (10).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 100110100000051 - 2⁴¹ = 97911076744499 is a prime.

It is a super-2 number, since 2×100110100000051² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100110099999983 and 100110100000037.

It is not a weakly prime, because it can be changed into another prime (100110100000061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50055050000025 + 50055050000026.

It is an arithmetic number, because the mean of its divisors is an integer number (50055050000026).

Almost surely, 2^{100110100000051} is an apocalyptic number.

100110100000051 is a deficient number, since it is larger than the sum of its proper divisors (1).

100110100000051 is an equidigital number, since it uses as much as digits as its factorization.

100110100000051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5, while the sum is 10.

Adding to 100110100000051 its reverse (150000001011001), we get a palindrome (250110101011052).

The spelling of 100110100000051 in words is "one hundred trillion, one hundred ten billion, one hundred million, fifty-one", and thus it is an aban number.