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100110122021047 is a prime number
BaseRepresentation
bin10110110000110010110100…
…010000101111000010110111
3111010110102201112022211001211
4112300302310100233002313
5101110201012214133142
6552525542151502251
730041501101652215
oct2660626420570267
9433412645284054
10100110122021047
1129997512019526
12b28a019387987
1343b24619c6948
141aa14da2b9cb5
15b8916246b917
hex5b0cb442f0b7

100110122021047 has 2 divisors, whose sum is σ = 100110122021048. Its totient is φ = 100110122021046.

The previous prime is 100110122020901. The next prime is 100110122021081. The reversal of 100110122021047 is 740120221011001.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (740120221011001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100110122021047 - 231 = 100107974537399 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100110122021947) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50055061010523 + 50055061010524.

It is an arithmetic number, because the mean of its divisors is an integer number (50055061010524).

Almost surely, 2100110122021047 is an apocalyptic number.

100110122021047 is a deficient number, since it is larger than the sum of its proper divisors (1).

100110122021047 is an equidigital number, since it uses as much as digits as its factorization.

100110122021047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 224, while the sum is 22.

Adding to 100110122021047 its reverse (740120221011001), we get a palindrome (840230343032048).

The spelling of 100110122021047 in words is "one hundred trillion, one hundred ten billion, one hundred twenty-two million, twenty-one thousand, forty-seven".