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100110211100047 is a prime number
BaseRepresentation
bin10110110000110010111001…
…100100100010110110001111
3111010110102221201221111111001
4112300302321210202312033
5101110201203020200142
6552525555053041131
730041503233060601
oct2660627144426617
9433412851844431
10100110211100047
1129997558330935
12b28a0431861a7
1343b24772b5605
141aa1508067171
15b8916a1b55b7
hex5b0cb9922d8f

100110211100047 has 2 divisors, whose sum is σ = 100110211100048. Its totient is φ = 100110211100046.

The previous prime is 100110211099967. The next prime is 100110211100117. The reversal of 100110211100047 is 740001112011001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 100110211100047 - 27 = 100110211099919 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100110211099997 and 100110211100033.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100110211103047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50055105550023 + 50055105550024.

It is an arithmetic number, because the mean of its divisors is an integer number (50055105550024).

Almost surely, 2100110211100047 is an apocalyptic number.

100110211100047 is a deficient number, since it is larger than the sum of its proper divisors (1).

100110211100047 is an equidigital number, since it uses as much as digits as its factorization.

100110211100047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56, while the sum is 19.

Adding to 100110211100047 its reverse (740001112011001), we get a palindrome (840111323111048).

The spelling of 100110211100047 in words is "one hundred trillion, one hundred ten billion, two hundred eleven million, one hundred thousand, forty-seven".