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100110211100117 is a prime number
BaseRepresentation
bin10110110000110010111001…
…100100100010110111010101
3111010110102221201221111120122
4112300302321210202313111
5101110201203020200432
6552525555053041325
730041503233061031
oct2660627144426725
9433412851844518
10100110211100117
1129997558330999
12b28a043186245
1343b24772b565a
141aa15080671c1
15b8916a1b5612
hex5b0cb9922dd5

100110211100117 has 2 divisors, whose sum is σ = 100110211100118. Its totient is φ = 100110211100116.

The previous prime is 100110211100047. The next prime is 100110211100129. The reversal of 100110211100117 is 711001112011001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 98834635116721 + 1275575983396 = 9941561^2 + 1129414^2 .

It is a cyclic number.

It is not a de Polignac number, because 100110211100117 - 214 = 100110211083733 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100110211100095 and 100110211100104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100110211100177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50055105550058 + 50055105550059.

It is an arithmetic number, because the mean of its divisors is an integer number (50055105550059).

Almost surely, 2100110211100117 is an apocalyptic number.

It is an amenable number.

100110211100117 is a deficient number, since it is larger than the sum of its proper divisors (1).

100110211100117 is an equidigital number, since it uses as much as digits as its factorization.

100110211100117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14, while the sum is 17.

Adding to 100110211100117 its reverse (711001112011001), we get a palindrome (811111323111118).

The spelling of 100110211100117 in words is "one hundred trillion, one hundred ten billion, two hundred eleven million, one hundred thousand, one hundred seventeen".