10011040213 has 2 divisors, whose sum is σ = 10011040214. Its totient is φ = 10011040212.

The previous prime is 10011040199. The next prime is 10011040219. The reversal of 10011040213 is 31204011001.

10011040213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7683749649 + 2327290564 = 87657^2 + 48242^2 .

It is a cyclic number.

It is not a de Polignac number, because 10011040213 - 2¹⁷ = 10010909141 is a prime.

It is a super-2 number, since 2×10011040213² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10011040193 and 10011040202.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10011040219) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005520106 + 5005520107.

It is an arithmetic number, because the mean of its divisors is an integer number (5005520107).

Almost surely, 2^10011040213 is an apocalyptic number.

It is an amenable number.

10011040213 is a deficient number, since it is larger than the sum of its proper divisors (1).

10011040213 is an equidigital number, since it uses as much as digits as its factorization.

10011040213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 10011040213 its reverse (31204011001), we get a palindrome (41215051214).

The spelling of 10011040213 in words is "ten billion, eleven million, forty thousand, two hundred thirteen".