Base | Representation |
---|---|
bin | 10110110000110011110100… |
… | …100000111001110001111111 |
3 | 111010110112111122201212202212 |
4 | 112300303310200321301333 |
5 | 101110210214200014101 |
6 | 552530241140411035 |
7 | 30041536601434313 |
oct | 2660636440716177 |
9 | 433415448655685 |
10 | 100111200001151 |
11 | 29997a15563979 |
12 | b28a27a3a6a7b |
13 | 43b25a41379b1 |
14 | 1aa159d525b43 |
15 | b891c6e031bb |
hex | 5b0cf4839c7f |
100111200001151 has 2 divisors, whose sum is σ = 100111200001152. Its totient is φ = 100111200001150.
The previous prime is 100111200001081. The next prime is 100111200001187. The reversal of 100111200001151 is 151100002111001.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100111200001151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100111200001451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50055600000575 + 50055600000576.
It is an arithmetic number, because the mean of its divisors is an integer number (50055600000576).
Almost surely, 2100111200001151 is an apocalyptic number.
100111200001151 is a deficient number, since it is larger than the sum of its proper divisors (1).
100111200001151 is an equidigital number, since it uses as much as digits as its factorization.
100111200001151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10, while the sum is 14.
Adding to 100111200001151 its reverse (151100002111001), we get a palindrome (251211202112152).
The spelling of 100111200001151 in words is "one hundred trillion, one hundred eleven billion, two hundred million, one thousand, one hundred fifty-one".
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