10011122411341 has 2 divisors, whose sum is σ = 10011122411342. Its totient is φ = 10011122411340.

The previous prime is 10011122411327. The next prime is 10011122411363. The reversal of 10011122411341 is 14311422111001.

10011122411341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an a-pointer prime, because the next prime (10011122411363) can be obtained adding 10011122411341 to its sum of digits (22).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8124837168100 + 1886285243241 = 2850410^2 + 1373421^2 .

It is an emirp because it is prime and its reverse (14311422111001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10011122411341 - 2¹⁵ = 10011122378573 is a prime.

It is a super-3 number, since 3×10011122411341³ (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10011122411041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005561205670 + 5005561205671.

It is an arithmetic number, because the mean of its divisors is an integer number (5005561205671).

Almost surely, 2^{10011122411341} is an apocalyptic number.

It is an amenable number.

10011122411341 is a deficient number, since it is larger than the sum of its proper divisors (1).

10011122411341 is an equidigital number, since it uses as much as digits as its factorization.

10011122411341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 22.

Adding to 10011122411341 its reverse (14311422111001), we get a palindrome (24322544522342).

The spelling of 10011122411341 in words is "ten trillion, eleven billion, one hundred twenty-two million, four hundred eleven thousand, three hundred forty-one".