Base | Representation |
---|---|
bin | 1001000110101110101010… |
… | …1000010000001001001111 |
3 | 1022110001200110020102211211 |
4 | 2101223222220100021033 |
5 | 2303010424304020421 |
6 | 33143030402555251 |
7 | 2052200056551622 |
oct | 221535250201117 |
9 | 38401613212754 |
10 | 10011210220111 |
11 | 320a8041a5341 |
12 | 11582a6068b27 |
13 | 57808c7a7c69 |
14 | 26878bcc1db9 |
15 | 1256341a99e1 |
hex | 91aeaa1024f |
10011210220111 has 2 divisors, whose sum is σ = 10011210220112. Its totient is φ = 10011210220110.
The previous prime is 10011210220103. The next prime is 10011210220171. The reversal of 10011210220111 is 11102201211001.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10011210220111 - 23 = 10011210220103 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10011210220091 and 10011210220100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10011210220171) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005605110055 + 5005605110056.
It is an arithmetic number, because the mean of its divisors is an integer number (5005605110056).
Almost surely, 210011210220111 is an apocalyptic number.
10011210220111 is a deficient number, since it is larger than the sum of its proper divisors (1).
10011210220111 is an equidigital number, since it uses as much as digits as its factorization.
10011210220111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8, while the sum is 13.
Adding to 10011210220111 its reverse (11102201211001), we get a palindrome (21113411431112).
The spelling of 10011210220111 in words is "ten trillion, eleven billion, two hundred ten million, two hundred twenty thousand, one hundred eleven".
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