Base | Representation |
---|---|
bin | 1001000110101110101010… |
… | …1000111100011001000111 |
3 | 1022110001200110120122110102 |
4 | 2101223222220330121013 |
5 | 2303010424330320401 |
6 | 33143030410514315 |
7 | 2052200061235205 |
oct | 221535250743107 |
9 | 38401613518412 |
10 | 10011210401351 |
11 | 320a804309525 |
12 | 11582a613599b |
13 | 57808c83c5c3 |
14 | 26878bd2c075 |
15 | 1256341e356b |
hex | 91aeaa3c647 |
10011210401351 has 2 divisors, whose sum is σ = 10011210401352. Its totient is φ = 10011210401350.
The previous prime is 10011210401333. The next prime is 10011210401371. The reversal of 10011210401351 is 15310401211001.
10011210401351 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an a-pointer prime, because the next prime (10011210401371) can be obtained adding 10011210401351 to its sum of digits (20).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10011210401351 - 238 = 9736332494407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10011210401371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005605200675 + 5005605200676.
It is an arithmetic number, because the mean of its divisors is an integer number (5005605200676).
Almost surely, 210011210401351 is an apocalyptic number.
10011210401351 is a deficient number, since it is larger than the sum of its proper divisors (1).
10011210401351 is an equidigital number, since it uses as much as digits as its factorization.
10011210401351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120, while the sum is 20.
Adding to 10011210401351 its reverse (15310401211001), we get a palindrome (25321611612352).
The spelling of 10011210401351 in words is "ten trillion, eleven billion, two hundred ten million, four hundred one thousand, three hundred fifty-one".
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