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10011303013 is a prime number
BaseRepresentation
bin10010101001011100…
…00101110001100101
3221211201000212221111
421110232011301211
5131000343144023
64333224545021
7503042446225
oct112456056145
927751025844
1010011303013
114278135148
121b34922171
13c3714714a
146ad866085
153d8d9200d
hex254b85c65

10011303013 has 2 divisors, whose sum is σ = 10011303014. Its totient is φ = 10011303012.

The previous prime is 10011302971. The next prime is 10011303017. The reversal of 10011303013 is 31030311001.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7867335204 + 2143967809 = 88698^2 + 46303^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10011303013 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10011302984 and 10011303002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10011303017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005651506 + 5005651507.

It is an arithmetic number, because the mean of its divisors is an integer number (5005651507).

Almost surely, 210011303013 is an apocalyptic number.

It is an amenable number.

10011303013 is a deficient number, since it is larger than the sum of its proper divisors (1).

10011303013 is an equidigital number, since it uses as much as digits as its factorization.

10011303013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27, while the sum is 13.

Adding to 10011303013 its reverse (31030311001), we get a palindrome (41041614014).

The spelling of 10011303013 in words is "ten billion, eleven million, three hundred three thousand, thirteen".