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10011303119 is a prime number
BaseRepresentation
bin10010101001011100…
…00101110011001111
3221211201000220002102
421110232011303033
5131000343144434
64333224545315
7503042446436
oct112456056317
927751026072
1010011303119
114278135234
121b3492223b
13c371471cc
146ad86611d
153d8d9207e
hex254b85ccf

10011303119 has 2 divisors, whose sum is σ = 10011303120. Its totient is φ = 10011303118.

The previous prime is 10011303101. The next prime is 10011303131. The reversal of 10011303119 is 91130311001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10011303119 - 216 = 10011237583 is a prime.

It is a super-2 number, since 2×100113031192 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 10011303119.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10011363119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005651559 + 5005651560.

It is an arithmetic number, because the mean of its divisors is an integer number (5005651560).

Almost surely, 210011303119 is an apocalyptic number.

10011303119 is a deficient number, since it is larger than the sum of its proper divisors (1).

10011303119 is an equidigital number, since it uses as much as digits as its factorization.

10011303119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81, while the sum is 20.

The spelling of 10011303119 in words is "ten billion, eleven million, three hundred three thousand, one hundred nineteen".