Base | Representation |
---|---|
bin | 10010101001011100… |
… | …00101110011011011 |
3 | 221211201000220002212 |
4 | 21110232011303123 |
5 | 131000343200011 |
6 | 4333224545335 |
7 | 503042446454 |
oct | 112456056333 |
9 | 27751026085 |
10 | 10011303131 |
11 | 4278135245 |
12 | 1b3492224b |
13 | c3714720b |
14 | 6ad86612b |
15 | 3d8d9208b |
hex | 254b85cdb |
10011303131 has 2 divisors, whose sum is σ = 10011303132. Its totient is φ = 10011303130.
The previous prime is 10011303119. The next prime is 10011303163. The reversal of 10011303131 is 13130311001.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10011303131 - 26 = 10011303067 is a prime.
It is a super-2 number, since 2×100113031312 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10011303101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005651565 + 5005651566.
It is an arithmetic number, because the mean of its divisors is an integer number (5005651566).
Almost surely, 210011303131 is an apocalyptic number.
10011303131 is a deficient number, since it is larger than the sum of its proper divisors (1).
10011303131 is an equidigital number, since it uses as much as digits as its factorization.
10011303131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27, while the sum is 14.
Adding to 10011303131 its reverse (13130311001), we get a palindrome (23141614132).
The spelling of 10011303131 in words is "ten billion, eleven million, three hundred three thousand, one hundred thirty-one".
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