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100113103151 is a prime number
BaseRepresentation
bin101110100111100110…
…1001011100100101111
3100120102001110120121022
41131033031023210233
53120012423300101
6113554043124355
710142616223205
oct1351715134457
9316361416538
10100113103151
1139504267186
121749b8136bb
139596090399
144bba0a3075
15290e12ba1b
hex174f34b92f

100113103151 has 2 divisors, whose sum is σ = 100113103152. Its totient is φ = 100113103150.

The previous prime is 100113103033. The next prime is 100113103201. The reversal of 100113103151 is 151301311001.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100113103151 is a prime.

It is a super-2 number, since 2×1001131031512 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100113106151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50056551575 + 50056551576.

It is an arithmetic number, because the mean of its divisors is an integer number (50056551576).

Almost surely, 2100113103151 is an apocalyptic number.

100113103151 is a deficient number, since it is larger than the sum of its proper divisors (1).

100113103151 is an equidigital number, since it uses as much as digits as its factorization.

100113103151 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 45, while the sum is 17.

Adding to 100113103151 its reverse (151301311001), we get a palindrome (251414414152).

The spelling of 100113103151 in words is "one hundred billion, one hundred thirteen million, one hundred three thousand, one hundred fifty-one".