Base | Representation |
---|---|
bin | 11101001000110001011… |
… | …11001110011010100111 |
3 | 10112201010100002000110102 |
4 | 32210120233032122213 |
5 | 112400314424203332 |
6 | 2043530220214315 |
7 | 132221146050044 |
oct | 16443057163247 |
9 | 3481110060412 |
10 | 1001142412967 |
11 | 356644879744 |
12 | 14204069a39b |
13 | 7353ab79448 |
14 | 366540661cb |
15 | 1b096bc9062 |
hex | e918bce6a7 |
1001142412967 has 2 divisors, whose sum is σ = 1001142412968. Its totient is φ = 1001142412966.
The previous prime is 1001142412951. The next prime is 1001142413021. The reversal of 1001142412967 is 7692142411001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1001142412967 - 24 = 1001142412951 is a prime.
It is a super-2 number, since 2×10011424129672 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1001142412967.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1001142417967) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500571206483 + 500571206484.
It is an arithmetic number, because the mean of its divisors is an integer number (500571206484).
Almost surely, 21001142412967 is an apocalyptic number.
1001142412967 is a deficient number, since it is larger than the sum of its proper divisors (1).
1001142412967 is an equidigital number, since it uses as much as digits as its factorization.
1001142412967 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24192, while the sum is 38.
Adding to 1001142412967 its reverse (7692142411001), we get a palindrome (8693284823968).
The spelling of 1001142412967 in words is "one trillion, one billion, one hundred forty-two million, four hundred twelve thousand, nine hundred sixty-seven".
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