Base | Representation |
---|---|
bin | 10110110000111100000001… |
… | …000110011110010010011101 |
3 | 111010111101020000120121001121 |
4 | 112300330001012132102131 |
5 | 101110331230241024242 |
6 | 552534254335010541 |
7 | 30042300650563264 |
oct | 2660740106362235 |
9 | 433441200517047 |
10 | 100120001111197 |
11 | 299a0721560141 |
12 | b28bb15969a51 |
13 | 43b337762c012 |
14 | 1aa1b963675db |
15 | b8953e8e4667 |
hex | 5b0f0119e49d |
100120001111197 has 2 divisors, whose sum is σ = 100120001111198. Its totient is φ = 100120001111196.
The previous prime is 100120001111111. The next prime is 100120001111213. The reversal of 100120001111197 is 791111100021001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 60531605402436 + 39588395708761 = 7780206^2 + 6291931^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100120001111197 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100120001121197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50060000555598 + 50060000555599.
It is an arithmetic number, because the mean of its divisors is an integer number (50060000555599).
Almost surely, 2100120001111197 is an apocalyptic number.
It is an amenable number.
100120001111197 is a deficient number, since it is larger than the sum of its proper divisors (1).
100120001111197 is an equidigital number, since it uses as much as digits as its factorization.
100120001111197 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 126, while the sum is 25.
Adding to 100120001111197 its reverse (791111100021001), we get a palindrome (891231101132198).
The spelling of 100120001111197 in words is "one hundred trillion, one hundred twenty billion, one million, one hundred eleven thousand, one hundred ninety-seven".
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