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100120112120993 is a prime number
BaseRepresentation
bin10110110000111100000111…
…101101111100010010100001
3111010111101111202110110212112
4112300330013231330102201
5101110331442200332433
6552534313342205105
730042303466262066
oct2660740755742241
9433441452413775
10100120112120993
11299a0779191478
12b28bb46b83795
1343b3394628ba3
141aa1ba6dc2c6d
15b89549521348
hex5b0f07b7c4a1

100120112120993 has 2 divisors, whose sum is σ = 100120112120994. Its totient is φ = 100120112120992.

The previous prime is 100120112120971. The next prime is 100120112121049. The reversal of 100120112120993 is 399021211021001.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 71731803508369 + 28388308612624 = 8469463^2 + 5328068^2 .

It is a cyclic number.

It is not a de Polignac number, because 100120112120993 - 210 = 100120112119969 is a prime.

It is a super-2 number, since 2×1001201121209932 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (100120114120993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50060056060496 + 50060056060497.

It is an arithmetic number, because the mean of its divisors is an integer number (50060056060497).

Almost surely, 2100120112120993 is an apocalyptic number.

It is an amenable number.

100120112120993 is a deficient number, since it is larger than the sum of its proper divisors (1).

100120112120993 is an equidigital number, since it uses as much as digits as its factorization.

100120112120993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 32.

Adding to 100120112120993 its reverse (399021211021001), we get a palindrome (499141323141994).

The spelling of 100120112120993 in words is "one hundred trillion, one hundred twenty billion, one hundred twelve million, one hundred twenty thousand, nine hundred ninety-three".