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100120235534183 is a prime number
BaseRepresentation
bin10110110000111100001111…
…000100101110011101100111
3111010111101211100200111221102
4112300330033010232131213
5101110332220244043213
6552534333511310315
730042306525260234
oct2660741704563547
9433441740614842
10100120235534183
11299a0831914647
12b28bb8037b39b
1343b33b4079547
141aa1bb954a78b
15b8955529d158
hex5b0f0f12e767

100120235534183 has 2 divisors, whose sum is σ = 100120235534184. Its totient is φ = 100120235534182.

The previous prime is 100120235534167. The next prime is 100120235534213. The reversal of 100120235534183 is 381435532021001.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 100120235534183 - 24 = 100120235534167 is a prime.

It is a super-2 number, since 2×1001202355341832 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100120235537183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50060117767091 + 50060117767092.

It is an arithmetic number, because the mean of its divisors is an integer number (50060117767092).

Almost surely, 2100120235534183 is an apocalyptic number.

100120235534183 is a deficient number, since it is larger than the sum of its proper divisors (1).

100120235534183 is an equidigital number, since it uses as much as digits as its factorization.

100120235534183 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 86400, while the sum is 38.

Adding to 100120235534183 its reverse (381435532021001), we get a palindrome (481555767555184).

The spelling of 100120235534183 in words is "one hundred trillion, one hundred twenty billion, two hundred thirty-five million, five hundred thirty-four thousand, one hundred eighty-three".