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100120999499 is a prime number
BaseRepresentation
bin101110100111110101…
…1010011011001001011
3100120102121022202100122
41131033223103121023
53120021433440444
6113554524253455
710143043311503
oct1351753233113
9316377282318
10100120999499
113950876a894
12174a23a128b
1395978c6591
144bbb15aa03
15290eb8b4ee
hex174fad364b

100120999499 has 2 divisors, whose sum is σ = 100120999500. Its totient is φ = 100120999498.

The previous prime is 100120999471. The next prime is 100120999501. The reversal of 100120999499 is 994999021001.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100120999499 is a prime.

Together with 100120999501, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 100120999499.

It is not a weakly prime, because it can be changed into another prime (100120990499) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50060499749 + 50060499750.

It is an arithmetic number, because the mean of its divisors is an integer number (50060499750).

Almost surely, 2100120999499 is an apocalyptic number.

100120999499 is a deficient number, since it is larger than the sum of its proper divisors (1).

100120999499 is an equidigital number, since it uses as much as digits as its factorization.

100120999499 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 472392, while the sum is 53.

The spelling of 100120999499 in words is "one hundred billion, one hundred twenty million, nine hundred ninety-nine thousand, four hundred ninety-nine".