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1001212120949 is a prime number
BaseRepresentation
bin11101001000111001110…
…01001000111101110101
310112201022012020112211112
432210130321020331311
5112400440300332244
62043541150244405
7132222653416235
oct16443471107565
93481265215745
101001212120949
11356680160347
1214205bab6705
137354c445081
143665d40dcc5
151b09cd9839e
hexe91ce48f75

1001212120949 has 2 divisors, whose sum is σ = 1001212120950. Its totient is φ = 1001212120948.

The previous prime is 1001212120939. The next prime is 1001212121017. The reversal of 1001212120949 is 9490212121001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 745295523025 + 255916597924 = 863305^2 + 505882^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1001212120949 is a prime.

It is a super-4 number, since 4×10012121209494 (a number of 49 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1001212120939) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500606060474 + 500606060475.

It is an arithmetic number, because the mean of its divisors is an integer number (500606060475).

Almost surely, 21001212120949 is an apocalyptic number.

It is an amenable number.

1001212120949 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001212120949 is an equidigital number, since it uses as much as digits as its factorization.

1001212120949 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 32.

The spelling of 1001212120949 in words is "one trillion, one billion, two hundred twelve million, one hundred twenty thousand, nine hundred forty-nine".