100121312113 has 2 divisors, whose sum is σ = 100121312114. Its totient is φ = 100121312112.

The previous prime is 100121312087. The next prime is 100121312129. The reversal of 100121312113 is 311213121001.

It is a happy number.

It is an a-pointer prime, because the next prime (100121312129) can be obtained adding 100121312113 to its sum of digits (16).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 99487883889 + 633428224 = 315417^2 + 25168^2 .

It is an emirp because it is prime and its reverse (311213121001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100121312113 - 2¹³ = 100121303921 is a prime.

It is not a weakly prime, because it can be changed into another prime (100121312153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50060656056 + 50060656057.

It is an arithmetic number, because the mean of its divisors is an integer number (50060656057).

Almost surely, 2^100121312113 is an apocalyptic number.

It is an amenable number.

100121312113 is a deficient number, since it is larger than the sum of its proper divisors (1).

100121312113 is an equidigital number, since it uses as much as digits as its factorization.

100121312113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 16.

Adding to 100121312113 its reverse (311213121001), we get a palindrome (411334433114).

The spelling of 100121312113 in words is "one hundred billion, one hundred twenty-one million, three hundred twelve thousand, one hundred thirteen".