1001213233331 has 2 divisors, whose sum is σ = 1001213233332. Its totient is φ = 1001213233330.

The previous prime is 1001213233303. The next prime is 1001213233333. The reversal of 1001213233331 is 1333323121001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1001213233331 - 2¹⁰ = 1001213232307 is a prime.

It is a super-2 number, since 2×1001213233331² (a number of 25 digits) contains 22 as substring.

Together with 1001213233333, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1001213233297 and 1001213233306.

It is not a weakly prime, because it can be changed into another prime (1001213233333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500606616665 + 500606616666.

It is an arithmetic number, because the mean of its divisors is an integer number (500606616666).

Almost surely, 2^{1001213233331} is an apocalyptic number.

1001213233331 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001213233331 is an equidigital number, since it uses as much as digits as its factorization.

1001213233331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 1001213233331 its reverse (1333323121001), we get a palindrome (2334536354332).

The spelling of 1001213233331 in words is "one trillion, one billion, two hundred thirteen million, two hundred thirty-three thousand, three hundred thirty-one".