10012133111 has 2 divisors, whose sum is σ = 10012133112. Its totient is φ = 10012133110.

The previous prime is 10012133093. The next prime is 10012133143. The reversal of 10012133111 is 11133121001.

It is a happy number.

10012133111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (11133121001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10012133111 - 2¹⁰ = 10012132087 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10012132111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006066555 + 5006066556.

It is an arithmetic number, because the mean of its divisors is an integer number (5006066556).

Almost surely, 2^10012133111 is an apocalyptic number.

10012133111 is a deficient number, since it is larger than the sum of its proper divisors (1).

10012133111 is an equidigital number, since it uses as much as digits as its factorization.

10012133111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 10012133111 its reverse (11133121001), we get a palindrome (21145254112).

The spelling of 10012133111 in words is "ten billion, twelve million, one hundred thirty-three thousand, one hundred eleven".