Base | Representation |
---|---|
bin | 1001000110110010011001… |
… | …0010101100000011100111 |
3 | 1022110011021012202111102121 |
4 | 2101230212102230003213 |
5 | 2303020002031401411 |
6 | 33143314001250411 |
7 | 2052233633004202 |
oct | 221544622540347 |
9 | 38404235674377 |
10 | 10012211200231 |
11 | 3210178228539 |
12 | 1158525333a07 |
13 | 5781bbc992a6 |
14 | 268844c06939 |
15 | 125691ed1571 |
hex | 91b264ac0e7 |
10012211200231 has 2 divisors, whose sum is σ = 10012211200232. Its totient is φ = 10012211200230.
The previous prime is 10012211200217. The next prime is 10012211200247. The reversal of 10012211200231 is 13200211221001.
It is an a-pointer prime, because the next prime (10012211200247) can be obtained adding 10012211200231 to its sum of digits (16).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10012211200231 - 29 = 10012211199719 is a prime.
It is a super-2 number, since 2×100122112002312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10012211200261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006105600115 + 5006105600116.
It is an arithmetic number, because the mean of its divisors is an integer number (5006105600116).
Almost surely, 210012211200231 is an apocalyptic number.
10012211200231 is a deficient number, since it is larger than the sum of its proper divisors (1).
10012211200231 is an equidigital number, since it uses as much as digits as its factorization.
10012211200231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 10012211200231 its reverse (13200211221001), we get a palindrome (23212422421232).
The spelling of 10012211200231 in words is "ten trillion, twelve billion, two hundred eleven million, two hundred thousand, two hundred thirty-one".
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