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10012231109983 is a prime number
BaseRepresentation
bin1001000110110010011101…
…1110101000110101011111
31022110011022121020000110211
42101230213132220311133
52303020022131004413
633143315552113251
72052234264146134
oct221544736506537
938404277200424
1010012231109983
113210188496a83
12115852bb35827
135781c314a5cb
1426884770a58b
15125693b1583d
hex91b277a8d5f

10012231109983 has 2 divisors, whose sum is σ = 10012231109984. Its totient is φ = 10012231109982.

The previous prime is 10012231109977. The next prime is 10012231110023. The reversal of 10012231109983 is 38990113221001.

It is an a-pointer prime, because the next prime (10012231110023) can be obtained adding 10012231109983 to its sum of digits (40).

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10012231109983 is a prime.

It is a super-2 number, since 2×100122311099832 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10012231149983) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006115554991 + 5006115554992.

It is an arithmetic number, because the mean of its divisors is an integer number (5006115554992).

Almost surely, 210012231109983 is an apocalyptic number.

10012231109983 is a deficient number, since it is larger than the sum of its proper divisors (1).

10012231109983 is an equidigital number, since it uses as much as digits as its factorization.

10012231109983 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23328, while the sum is 40.

The spelling of 10012231109983 in words is "ten trillion, twelve billion, two hundred thirty-one million, one hundred nine thousand, nine hundred eighty-three".