Base | Representation |
---|---|
bin | 10010101001101001… |
… | …00100100100000111 |
3 | 221211211020012111121 |
4 | 21110310210210013 |
5 | 131001312030431 |
6 | 4333325214411 |
7 | 503063053426 |
oct | 112464444407 |
9 | 27754205447 |
10 | 10013001991 |
11 | 4279095663 |
12 | 1b35401407 |
13 | c375c0565 |
14 | 6adb892bd |
15 | 3d90ca611 |
hex | 254d24907 |
10013001991 has 2 divisors, whose sum is σ = 10013001992. Its totient is φ = 10013001990.
The previous prime is 10013001961. The next prime is 10013002079. The reversal of 10013001991 is 19910031001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10013001991 - 213 = 10012993799 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10013001961) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006500995 + 5006500996.
It is an arithmetic number, because the mean of its divisors is an integer number (5006500996).
Almost surely, 210013001991 is an apocalyptic number.
10013001991 is a deficient number, since it is larger than the sum of its proper divisors (1).
10013001991 is an equidigital number, since it uses as much as digits as its factorization.
10013001991 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243, while the sum is 25.
Adding to 10013001991 its reverse (19910031001), we get a palindrome (29923032992).
The spelling of 10013001991 in words is "ten billion, thirteen million, one thousand, nine hundred ninety-one".
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