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100131221110093 is a prime number
BaseRepresentation
bin10110110001000110011101…
…110111010111110101001101
3111010112110011221222121001021
4112301012131313113311031
5101111022220101010333
6552543351542314141
730043146001156315
oct2661063567276515
9433473157877037
10100131221110093
11299a54599a03a8
12b292127428951
1343b4444cc3714
141aa253c544445
15b8999993d82d
hex5b119ddd7d4d

100131221110093 has 2 divisors, whose sum is σ = 100131221110094. Its totient is φ = 100131221110092.

The previous prime is 100131221110087. The next prime is 100131221110103. The reversal of 100131221110093 is 390011122131001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 84896266482889 + 15234954627204 = 9213917^2 + 3903198^2 .

It is a cyclic number.

It is not a de Polignac number, because 100131221110093 - 217 = 100131220979021 is a prime.

It is a super-2 number, since 2×1001312211100932 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100131221110003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50065610555046 + 50065610555047.

It is an arithmetic number, because the mean of its divisors is an integer number (50065610555047).

Almost surely, 2100131221110093 is an apocalyptic number.

It is an amenable number.

100131221110093 is a deficient number, since it is larger than the sum of its proper divisors (1).

100131221110093 is an equidigital number, since it uses as much as digits as its factorization.

100131221110093 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324, while the sum is 25.

Adding to 100131221110093 its reverse (390011122131001), we get a palindrome (490142343241094).

The spelling of 100131221110093 in words is "one hundred trillion, one hundred thirty-one billion, two hundred twenty-one million, one hundred ten thousand, ninety-three".