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100132142353 is a prime number
BaseRepresentation
bin101110101000001010…
…1110011110100010001
3100120110101021212110221
41131100111303310101
53120032312023403
6114000003153041
710143240111115
oct1352025636421
9316411255427
10100132142353
1139513a90661
12174a6075781
139599cc8399
144bbc81b745
152910b3cdbd
hex1750573d11

100132142353 has 2 divisors, whose sum is σ = 100132142354. Its totient is φ = 100132142352.

The previous prime is 100132142333. The next prime is 100132142371. The reversal of 100132142353 is 353241231001.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 98227081744 + 1905060609 = 313412^2 + 43647^2 .

It is an emirp because it is prime and its reverse (353241231001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100132142353 - 213 = 100132134161 is a prime.

It is not a weakly prime, because it can be changed into another prime (100132142333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50066071176 + 50066071177.

It is an arithmetic number, because the mean of its divisors is an integer number (50066071177).

Almost surely, 2100132142353 is an apocalyptic number.

It is an amenable number.

100132142353 is a deficient number, since it is larger than the sum of its proper divisors (1).

100132142353 is an equidigital number, since it uses as much as digits as its factorization.

100132142353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 100132142353 its reverse (353241231001), we get a palindrome (453373373354).

The spelling of 100132142353 in words is "one hundred billion, one hundred thirty-two million, one hundred forty-two thousand, three hundred fifty-three".