Search a number
-
+
10013310997 is a prime number
BaseRepresentation
bin10010101001101011…
…10000000000010101
3221211211210220101021
421110311300000111
5131001401422442
64333340001141
7503065511344
oct112465600025
927754726337
1010013310997
114279286838
121b355301b1
13c3769b0c1
146adc29b5b
153d913be67
hex254d70015

10013310997 has 2 divisors, whose sum is σ = 10013310998. Its totient is φ = 10013310996.

The previous prime is 10013310959. The next prime is 10013311003. The reversal of 10013310997 is 79901331001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7620242436 + 2393068561 = 87294^2 + 48919^2 .

It is a cyclic number.

It is not a de Polignac number, because 10013310997 - 231 = 7865827349 is a prime.

It is a super-2 number, since 2×100133109972 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10013310497) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006655498 + 5006655499.

It is an arithmetic number, because the mean of its divisors is an integer number (5006655499).

Almost surely, 210013310997 is an apocalyptic number.

It is an amenable number.

10013310997 is a deficient number, since it is larger than the sum of its proper divisors (1).

10013310997 is an equidigital number, since it uses as much as digits as its factorization.

10013310997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5103, while the sum is 34.

Adding to 10013310997 its reverse (79901331001), we get a palindrome (89914641998).

The spelling of 10013310997 in words is "ten billion, thirteen million, three hundred ten thousand, nine hundred ninety-seven".