Base | Representation |
---|---|
bin | 10110110001001000001110… |
… | …101001001111111011110111 |
3 | 111010112122001211100101220202 |
4 | 112301020032221033323313 |
5 | 101111040103441430033 |
6 | 552544303413151115 |
7 | 30043243615021124 |
oct | 2661101651177367 |
9 | 433478054311822 |
10 | 100133113233143 |
11 | 299a623aa56461 |
12 | b29257502b49b |
13 | 43b4686cc9b63 |
14 | 1aa267b95b74b |
15 | b89a5aae28e8 |
hex | 5b120ea4fef7 |
100133113233143 has 2 divisors, whose sum is σ = 100133113233144. Its totient is φ = 100133113233142.
The previous prime is 100133113233091. The next prime is 100133113233173. The reversal of 100133113233143 is 341332311331001.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100133113233143 is a prime.
It is a super-2 number, since 2×1001331132331432 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100133113233173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50066556616571 + 50066556616572.
It is an arithmetic number, because the mean of its divisors is an integer number (50066556616572).
Almost surely, 2100133113233143 is an apocalyptic number.
100133113233143 is a deficient number, since it is larger than the sum of its proper divisors (1).
100133113233143 is an equidigital number, since it uses as much as digits as its factorization.
100133113233143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5832, while the sum is 29.
Adding to 100133113233143 its reverse (341332311331001), we get a palindrome (441465424564144).
The spelling of 100133113233143 in words is "one hundred trillion, one hundred thirty-three billion, one hundred thirteen million, two hundred thirty-three thousand, one hundred forty-three".
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