Base | Representation |
---|---|
bin | 111011101011110… |
… | …100010010010101 |
3 | 2120210012110010111 |
4 | 323223310102111 |
5 | 4022320421401 |
6 | 243210123021 |
7 | 33546160504 |
oct | 7353642225 |
9 | 2523173114 |
10 | 1001342101 |
11 | 474260161 |
12 | 23b420471 |
13 | 12c5ba026 |
14 | 96dba83b |
15 | 5cd98e51 |
hex | 3baf4495 |
1001342101 has 2 divisors, whose sum is σ = 1001342102. Its totient is φ = 1001342100.
The previous prime is 1001342087. The next prime is 1001342107. The reversal of 1001342101 is 1012431001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 985897201 + 15444900 = 31399^2 + 3930^2 .
It is a cyclic number.
It is not a de Polignac number, because 1001342101 - 221 = 999244949 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1001342107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500671050 + 500671051.
It is an arithmetic number, because the mean of its divisors is an integer number (500671051).
Almost surely, 21001342101 is an apocalyptic number.
It is an amenable number.
1001342101 is a deficient number, since it is larger than the sum of its proper divisors (1).
1001342101 is an equidigital number, since it uses as much as digits as its factorization.
1001342101 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 13.
The square root of 1001342101 is about 31643.9899665007. The cubic root of 1001342101 is about 1000.4471670119.
Adding to 1001342101 its reverse (1012431001), we get a palindrome (2013773102).
Subtracting 1001342101 from its reverse (1012431001), we obtain a square (11088900 = 33302).
The spelling of 1001342101 in words is "one billion, one million, three hundred forty-two thousand, one hundred one".
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