100140113 has 2 divisors, whose sum is σ = 100140114. Its totient is φ = 100140112.

The previous prime is 100140107. The next prime is 100140119. The reversal of 100140113 is 311041001.

It is a balanced prime because it is at equal distance from previous prime (100140107) and next prime (100140119).

It can be written as a sum of positive squares in only one way, i.e., 100140049 + 64 = 10007^2 + 8^2 .

It is a cyclic number.

It is not a de Polignac number, because 100140113 - 2¹⁰ = 100139089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100140094 and 100140103.

It is not a weakly prime, because it can be changed into another prime (100140119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50070056 + 50070057.

It is an arithmetic number, because the mean of its divisors is an integer number (50070057).

Almost surely, 2^100140113 is an apocalyptic number.

It is an amenable number.

100140113 is a deficient number, since it is larger than the sum of its proper divisors (1).

100140113 is an equidigital number, since it uses as much as digits as its factorization.

100140113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 100140113 is about 10007.0031977611. The cubic root of 100140113 is about 464.3755645054.

Adding to 100140113 its reverse (311041001), we get a palindrome (411181114).

It can be divided in two parts, 1001 and 40113, that added together give a palindrome (41114).

The spelling of 100140113 in words is "one hundred million, one hundred forty thousand, one hundred thirteen".