Base | Representation |
---|---|
bin | 101110101000011011… |
… | …1101000110110000111 |
3 | 100120110222222102000211 |
4 | 1131100313220312013 |
5 | 3120042044312221 |
6 | 114000521220251 |
7 | 10143405354166 |
oct | 1352067506607 |
9 | 316428872024 |
10 | 100141010311 |
11 | 39518a98251 |
12 | 174a9031687 |
13 | 959bab18b4 |
14 | 4bbda893dd |
15 | 29117e06e1 |
hex | 1750de8d87 |
100141010311 has 2 divisors, whose sum is σ = 100141010312. Its totient is φ = 100141010310.
The previous prime is 100141010269. The next prime is 100141010369. The reversal of 100141010311 is 113010141001.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 100141010311 - 217 = 100140879239 is a prime.
It is a super-2 number, since 2×1001410103112 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 100141010291 and 100141010300.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100141010911) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50070505155 + 50070505156.
It is an arithmetic number, because the mean of its divisors is an integer number (50070505156).
Almost surely, 2100141010311 is an apocalyptic number.
100141010311 is a deficient number, since it is larger than the sum of its proper divisors (1).
100141010311 is an equidigital number, since it uses as much as digits as its factorization.
100141010311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 100141010311 its reverse (113010141001), we get a palindrome (213151151312).
The spelling of 100141010311 in words is "one hundred billion, one hundred forty-one million, ten thousand, three hundred eleven".
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