Base | Representation |
---|---|
bin | 101110101000011100… |
… | …0011110011110110001 |
3 | 100120111000101120101111 |
4 | 1131100320132132301 |
5 | 3120042123330001 |
6 | 114000530033321 |
7 | 10143410260531 |
oct | 1352070363661 |
9 | 316430346344 |
10 | 100141230001 |
11 | 3951912830a |
12 | 174a9118841 |
13 | 959bb5a8a7 |
14 | 4bbdb054c1 |
15 | 2911835851 |
hex | 1750e1e7b1 |
100141230001 has 2 divisors, whose sum is σ = 100141230002. Its totient is φ = 100141230000.
The previous prime is 100141229999. The next prime is 100141230017. The reversal of 100141230001 is 100032141001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 99691747600 + 449482401 = 315740^2 + 21201^2 .
It is a cyclic number.
It is not a de Polignac number, because 100141230001 - 21 = 100141229999 is a prime.
It is a super-2 number, since 2×1001412300012 (a number of 23 digits) contains 22 as substring.
Together with 100141229999, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (100141230041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50070615000 + 50070615001.
It is an arithmetic number, because the mean of its divisors is an integer number (50070615001).
Almost surely, 2100141230001 is an apocalyptic number.
It is an amenable number.
100141230001 is a deficient number, since it is larger than the sum of its proper divisors (1).
100141230001 is an equidigital number, since it uses as much as digits as its factorization.
100141230001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 100141230001 its reverse (100032141001), we get a palindrome (200173371002).
The spelling of 100141230001 in words is "one hundred billion, one hundred forty-one million, two hundred thirty thousand, one".
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