Base | Representation |
---|---|
bin | 10110110001010001100100… |
… | …011110001100011010011111 |
3 | 111010120120221211022221210121 |
4 | 112301101210132030122133 |
5 | 101111221124114012203 |
6 | 552553042544215411 |
7 | 30044050304410366 |
oct | 2661214436143237 |
9 | 433516854287717 |
10 | 100143143110303 |
11 | 299aa517617637 |
12 | b2944b400a567 |
13 | 43b55c4c48407 |
14 | 1aa2d4da5a7dd |
15 | b89e464030bd |
hex | 5b146478c69f |
100143143110303 has 2 divisors, whose sum is σ = 100143143110304. Its totient is φ = 100143143110302.
The previous prime is 100143143110271. The next prime is 100143143110333. The reversal of 100143143110303 is 303011341341001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 100143143110303 - 25 = 100143143110271 is a prime.
It is a super-2 number, since 2×1001431431103032 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100143143110333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50071571555151 + 50071571555152.
It is an arithmetic number, because the mean of its divisors is an integer number (50071571555152).
Almost surely, 2100143143110303 is an apocalyptic number.
100143143110303 is a deficient number, since it is larger than the sum of its proper divisors (1).
100143143110303 is an equidigital number, since it uses as much as digits as its factorization.
100143143110303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 100143143110303 its reverse (303011341341001), we get a palindrome (403154484451304).
The spelling of 100143143110303 in words is "one hundred trillion, one hundred forty-three billion, one hundred forty-three million, one hundred ten thousand, three hundred three".
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