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100144424112167 is a prime number
BaseRepresentation
bin10110110001010010110000…
…110100110101000000100111
3111010120201021002202121000002
4112301102300310311000213
5101111231240033042132
6552553414024411515
730044124120633611
oct2661226064650047
9433521232677002
10100144424112167
1129a00014719266
12b2947b1016b9b
1343b576a460c96
141aa3031c33db1
15b89ebdade262
hex5b14b0d35027

100144424112167 has 2 divisors, whose sum is σ = 100144424112168. Its totient is φ = 100144424112166.

The previous prime is 100144424112107. The next prime is 100144424112253. The reversal of 100144424112167 is 761211424441001.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 100144424112167 - 220 = 100144423063591 is a prime.

It is a super-3 number, since 3×1001444241121673 (a number of 43 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 100144424112167.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100144424112107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50072212056083 + 50072212056084.

It is an arithmetic number, because the mean of its divisors is an integer number (50072212056084).

Almost surely, 2100144424112167 is an apocalyptic number.

100144424112167 is a deficient number, since it is larger than the sum of its proper divisors (1).

100144424112167 is an equidigital number, since it uses as much as digits as its factorization.

100144424112167 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43008, while the sum is 38.

Adding to 100144424112167 its reverse (761211424441001), we get a palindrome (861355848553168).

The spelling of 100144424112167 in words is "one hundred trillion, one hundred forty-four billion, four hundred twenty-four million, one hundred twelve thousand, one hundred sixty-seven".