10020022100111 has 2 divisors, whose sum is σ = 10020022100112. Its totient is φ = 10020022100110.

The previous prime is 10020022100083. The next prime is 10020022100113. The reversal of 10020022100111 is 11100122002001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10020022100111 - 2¹⁸ = 10020021837967 is a prime.

It is a Sophie Germain prime.

Together with 10020022100113, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10020022100092 and 10020022100101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10020022100113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5010011050055 + 5010011050056.

It is an arithmetic number, because the mean of its divisors is an integer number (5010011050056).

Almost surely, 2^{10020022100111} is an apocalyptic number.

10020022100111 is a deficient number, since it is larger than the sum of its proper divisors (1).

10020022100111 is an equidigital number, since it uses as much as digits as its factorization.

10020022100111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8, while the sum is 11.

Adding to 10020022100111 its reverse (11100122002001), we get a palindrome (21120144102112).

The spelling of 10020022100111 in words is "ten trillion, twenty billion, twenty-two million, one hundred thousand, one hundred eleven".