1002003011311 has 2 divisors, whose sum is σ = 1002003011312. Its totient is φ = 1002003011310.

The previous prime is 1002003011309. The next prime is 1002003011327. The reversal of 1002003011311 is 1131103002001.

1002003011311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1002003011311 - 2¹ = 1002003011309 is a prime.

Together with 1002003011309, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1002003011291 and 1002003011300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1002003041311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501001505655 + 501001505656.

It is an arithmetic number, because the mean of its divisors is an integer number (501001505656).

Almost surely, 2^{1002003011311} is an apocalyptic number.

1002003011311 is a deficient number, since it is larger than the sum of its proper divisors (1).

1002003011311 is an equidigital number, since it uses as much as digits as its factorization.

1002003011311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 1002003011311 its reverse (1131103002001), we get a palindrome (2133106013312).

The spelling of 1002003011311 in words is "one trillion, two billion, three million, eleven thousand, three hundred eleven".