100201213111 has 2 divisors, whose sum is σ = 100201213112. Its totient is φ = 100201213110.

The previous prime is 100201213043. The next prime is 100201213117. The reversal of 100201213111 is 111312102001.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (111312102001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100201213111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100201213091 and 100201213100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100201213117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50100606555 + 50100606556.

It is an arithmetic number, because the mean of its divisors is an integer number (50100606556).

Almost surely, 2^100201213111 is an apocalyptic number.

100201213111 is a deficient number, since it is larger than the sum of its proper divisors (1).

100201213111 is an equidigital number, since it uses as much as digits as its factorization.

100201213111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 100201213111 its reverse (111312102001), we get a palindrome (211513315112).

The spelling of 100201213111 in words is "one hundred billion, two hundred one million, two hundred thirteen thousand, one hundred eleven".