Base | Representation |
---|---|
bin | 10010101010011111… |
… | …10001001110011111 |
3 | 221212022122102200111 |
4 | 21111033301032133 |
5 | 131010123203433 |
6 | 4334142110451 |
7 | 503210500036 |
oct | 112517611637 |
9 | 27768572614 |
10 | 10020131743 |
11 | 4282115316 |
12 | 1b3787b427 |
13 | c38c1884b |
14 | 6b0ac371d |
15 | 3d9a37dcd |
hex | 2553f139f |
10020131743 has 2 divisors, whose sum is σ = 10020131744. Its totient is φ = 10020131742.
The previous prime is 10020131741. The next prime is 10020131747. The reversal of 10020131743 is 34713102001.
It is a weak prime.
It is an emirp because it is prime and its reverse (34713102001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10020131743 - 21 = 10020131741 is a prime.
It is a super-3 number, since 3×100201317433 (a number of 31 digits) contains 333 as substring.
Together with 10020131741, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10020131741) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5010065871 + 5010065872.
It is an arithmetic number, because the mean of its divisors is an integer number (5010065872).
Almost surely, 210020131743 is an apocalyptic number.
10020131743 is a deficient number, since it is larger than the sum of its proper divisors (1).
10020131743 is an equidigital number, since it uses as much as digits as its factorization.
10020131743 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 22.
Adding to 10020131743 its reverse (34713102001), we get a palindrome (44733233744).
The spelling of 10020131743 in words is "ten billion, twenty million, one hundred thirty-one thousand, seven hundred forty-three".
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