Base | Representation |
---|---|
bin | 101110101010100001… |
… | …1011101111000010101 |
3 | 100120122220002102121021 |
4 | 1131111003131320111 |
5 | 3120213033014424 |
6 | 114011510121141 |
7 | 10145220213136 |
oct | 1352503357025 |
9 | 316586072537 |
10 | 100211219989 |
11 | 39554691881 |
12 | 175086501b1 |
13 | 95b04c499a |
14 | 4bc9123c8d |
15 | 2917a5d4e4 |
hex | 17550dde15 |
100211219989 has 2 divisors, whose sum is σ = 100211219990. Its totient is φ = 100211219988.
The previous prime is 100211219981. The next prime is 100211220001. The reversal of 100211219989 is 989912112001.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 70641666225 + 29569553764 = 265785^2 + 171958^2 .
It is a cyclic number.
It is not a de Polignac number, because 100211219989 - 23 = 100211219981 is a prime.
It is a super-2 number, since 2×1002112199892 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100211219981) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50105609994 + 50105609995.
It is an arithmetic number, because the mean of its divisors is an integer number (50105609995).
Almost surely, 2100211219989 is an apocalyptic number.
It is an amenable number.
100211219989 is a deficient number, since it is larger than the sum of its proper divisors (1).
100211219989 is an equidigital number, since it uses as much as digits as its factorization.
100211219989 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23328, while the sum is 43.
The spelling of 100211219989 in words is "one hundred billion, two hundred eleven million, two hundred nineteen thousand, nine hundred eighty-nine".
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