Base | Representation |
---|---|
bin | 10110110010010001110011… |
… | …010001110110100010010111 |
3 | 111010211011222022121021010221 |
4 | 112302101303101312202113 |
5 | 101113333400404304233 |
6 | 553044450325455211 |
7 | 30052041350032162 |
oct | 2662216321664227 |
9 | 433734868537127 |
10 | 100212111009943 |
11 | 29a267991603a9 |
12 | b2a5941271507 |
13 | 43bbc665c689a |
14 | 1aa641356aad9 |
15 | b8bb310e142d |
hex | 5b2473476897 |
100212111009943 has 2 divisors, whose sum is σ = 100212111009944. Its totient is φ = 100212111009942.
The previous prime is 100212111009823. The next prime is 100212111010043. The reversal of 100212111009943 is 349900111212001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 100212111009943 - 221 = 100212108912791 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 100212111009899 and 100212111009908.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100212111069943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50106055504971 + 50106055504972.
It is an arithmetic number, because the mean of its divisors is an integer number (50106055504972).
Almost surely, 2100212111009943 is an apocalyptic number.
100212111009943 is a deficient number, since it is larger than the sum of its proper divisors (1).
100212111009943 is an equidigital number, since it uses as much as digits as its factorization.
100212111009943 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 34.
The spelling of 100212111009943 in words is "one hundred trillion, two hundred twelve billion, one hundred eleven million, nine thousand, nine hundred forty-three".
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