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1002212020127 is a prime number
BaseRepresentation
bin11101001010110000111…
…11011100111110011111
310112210212212201200122102
432211120133130332133
5112410012234121002
62044224305435315
7132256514420213
oct16453037347637
93483785650572
101002212020127
113570436153aa
1214229a93bb3b
137367b6483a6
1436716132943
151b10aa59a02
hexe9587dcf9f

1002212020127 has 2 divisors, whose sum is σ = 1002212020128. Its totient is φ = 1002212020126.

The previous prime is 1002212020099. The next prime is 1002212020129. The reversal of 1002212020127 is 7210202122001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1002212020127 - 28 = 1002212019871 is a prime.

It is a super-2 number, since 2×10022120201272 (a number of 25 digits) contains 22 as substring.

Together with 1002212020129, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1002212020099 and 1002212020108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1002212020129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501106010063 + 501106010064.

It is an arithmetic number, because the mean of its divisors is an integer number (501106010064).

Almost surely, 21002212020127 is an apocalyptic number.

1002212020127 is a deficient number, since it is larger than the sum of its proper divisors (1).

1002212020127 is an equidigital number, since it uses as much as digits as its factorization.

1002212020127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 224, while the sum is 20.

Adding to 1002212020127 its reverse (7210202122001), we get a palindrome (8212414142128).

The spelling of 1002212020127 in words is "one trillion, two billion, two hundred twelve million, twenty thousand, one hundred twenty-seven".