Base | Representation |
---|---|
bin | 10010101010111110… |
… | …11100100000110111 |
3 | 221212121101012210212 |
4 | 21111133130200313 |
5 | 131012201204312 |
6 | 4334410140035 |
7 | 503260434011 |
oct | 112537344067 |
9 | 27777335725 |
10 | 10024241207 |
11 | 4284471872 |
12 | 1b3912161b |
13 | c39a27196 |
14 | 6b14731b1 |
15 | 3da09a822 |
hex | 2557dc837 |
10024241207 has 2 divisors, whose sum is σ = 10024241208. Its totient is φ = 10024241206.
The previous prime is 10024241173. The next prime is 10024241209. The reversal of 10024241207 is 70214242001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10024241207 - 228 = 9755805751 is a prime.
It is a super-2 number, since 2×100242412072 (a number of 21 digits) contains 22 as substring.
Together with 10024241209, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10024241209) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5012120603 + 5012120604.
It is an arithmetic number, because the mean of its divisors is an integer number (5012120604).
Almost surely, 210024241207 is an apocalyptic number.
10024241207 is a deficient number, since it is larger than the sum of its proper divisors (1).
10024241207 is an equidigital number, since it uses as much as digits as its factorization.
10024241207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 896, while the sum is 23.
Adding to 10024241207 its reverse (70214242001), we get a palindrome (80238483208).
The spelling of 10024241207 in words is "ten billion, twenty-four million, two hundred forty-one thousand, two hundred seven".
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