Base | Representation |
---|---|
bin | 10110110010101110100110… |
… | …011101011000110100101011 |
3 | 111010221010210102111102121021 |
4 | 112302232212131120310223 |
5 | 101114340213304134201 |
6 | 553111003030153311 |
7 | 30054214561624633 |
oct | 2662564635306453 |
9 | 433833712442537 |
10 | 100243034443051 |
11 | 29a38917681395 |
12 | b2ab9314b2837 |
13 | 43c1b5409b2b6 |
14 | 1aa7b084b16c3 |
15 | b8c840d24ea1 |
hex | 5b2ba6758d2b |
100243034443051 has 2 divisors, whose sum is σ = 100243034443052. Its totient is φ = 100243034443050.
The previous prime is 100243034443049. The next prime is 100243034443187. The reversal of 100243034443051 is 150344430342001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 100243034443051 - 21 = 100243034443049 is a prime.
Together with 100243034443049, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 100243034442998 and 100243034443016.
It is not a weakly prime, because it can be changed into another prime (100243034441051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50121517221525 + 50121517221526.
It is an arithmetic number, because the mean of its divisors is an integer number (50121517221526).
Almost surely, 2100243034443051 is an apocalyptic number.
100243034443051 is a deficient number, since it is larger than the sum of its proper divisors (1).
100243034443051 is an equidigital number, since it uses as much as digits as its factorization.
100243034443051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69120, while the sum is 34.
Adding to 100243034443051 its reverse (150344430342001), we get a palindrome (250587464785052).
The spelling of 100243034443051 in words is "one hundred trillion, two hundred forty-three billion, thirty-four million, four hundred forty-three thousand, fifty-one".
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