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1002552530813 is a prime number
BaseRepresentation
bin11101001011011001100…
…10011001011101111101
310112211202121110102111022
432211230302121131331
5112411211421441223
62044322152033525
7132301120622561
oct16455462313575
93484677412438
101002552530813
113571a8849099
121423749928a5
137370405b2c2
143674944d6a1
151b12a8bbac8
hexe96cc9977d

1002552530813 has 2 divisors, whose sum is σ = 1002552530814. Its totient is φ = 1002552530812.

The previous prime is 1002552530807. The next prime is 1002552530887. The reversal of 1002552530813 is 3180352552001.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 786905603929 + 215646926884 = 887077^2 + 464378^2 .

It is a cyclic number.

It is not a de Polignac number, because 1002552530813 - 214 = 1002552514429 is a prime.

It is a super-3 number, since 3×10025525308133 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1002552430813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501276265406 + 501276265407.

It is an arithmetic number, because the mean of its divisors is an integer number (501276265407).

Almost surely, 21002552530813 is an apocalyptic number.

It is an amenable number.

1002552530813 is a deficient number, since it is larger than the sum of its proper divisors (1).

1002552530813 is an equidigital number, since it uses as much as digits as its factorization.

1002552530813 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36000, while the sum is 35.

The spelling of 1002552530813 in words is "one trillion, two billion, five hundred fifty-two million, five hundred thirty thousand, eight hundred thirteen".