10030000919 has 2 divisors, whose sum is σ = 10030000920. Its totient is φ = 10030000918.

The previous prime is 10030000889. The next prime is 10030000921. The reversal of 10030000919 is 91900003001.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10030000919 is a prime.

It is a super-2 number, since 2×10030000919² (a number of 21 digits) contains 22 as substring.

Together with 10030000921, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10030000894 and 10030000903.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10030000619) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5015000459 + 5015000460.

It is an arithmetic number, because the mean of its divisors is an integer number (5015000460).

Almost surely, 2^10030000919 is an apocalyptic number.

10030000919 is a deficient number, since it is larger than the sum of its proper divisors (1).

10030000919 is an equidigital number, since it uses as much as digits as its factorization.

10030000919 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243, while the sum is 23.

The spelling of 10030000919 in words is "ten billion, thirty million, nine hundred nineteen", and thus it is an aban number.